Можете или да направите това програмно, като използвате един от API за работа с RDF, или можете да го направите, като използвате инструменти за RDF заявки като SPARQL. И в двата случая ще искате да изтеглите онтологията на DBpedia (онтология на OWL, сериализирана в RDF/XML).
Използване на Jena API за итерация през тройки
Използвайки Jena, можете да заредите данните в Модел и след това използвайте listStatements, за да изберете изразите, които имат rdfs:subClassOf
като свой предикат. Имайте предвид, че null
се използва като заместващ знак.
import com.hp.hpl.jena.rdf.model.Model;
import com.hp.hpl.jena.rdf.model.ModelFactory;
import com.hp.hpl.jena.rdf.model.RDFNode;
import com.hp.hpl.jena.rdf.model.Statement;
import com.hp.hpl.jena.rdf.model.StmtIterator;
import com.hp.hpl.jena.vocabulary.RDFS;
public class IterateRDFSSubclassTriples {
public static void main(String[] args) {
final Model dbpedia = ModelFactory.createDefaultModel();
dbpedia.read( "/home/taylorj/Downloads/dbpedia_3.9.owl", "RDF/XML" );
final StmtIterator stmts = dbpedia.listStatements(null, RDFS.subClassOf, (RDFNode) null);
while ( stmts.hasNext() ) {
final Statement stmt = stmts.next();
System.out.println( stmt.getSubject() + " is a subclass of " + stmt.getObject() );
}
}
}
Това произвежда резултат като този:
http://dbpedia.org/ontology/FilmFestival is a subclass of http://schema.org/Festival
http://dbpedia.org/ontology/Embryology is a subclass of http://dbpedia.org/ontology/AnatomicalStructure
http://dbpedia.org/ontology/Canal is a subclass of http://dbpedia.org/ontology/Stream
http://dbpedia.org/ontology/Fern is a subclass of http://dbpedia.org/ontology/Plant
http://dbpedia.org/ontology/Architect is a subclass of http://dbpedia.org/ontology/Person
…
Използване на SPARQL
Можете да изпълните следната SPARQL заявка, за да извлечете всички подкласове и суперкласове от rdfs:subClassOf
тройки:
prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#>
select ?subclass ?superclass where {
?subclass rdfs:subClassOf ?superclass
}
Използвайки инструмента sparql
на командния ред на Jena, намираме 541 такива тройки:
$ sparql --query query.rq --data dbpedia_3.9.owl | head
-----------------------------------------------------------------------------------------------------------------------------------------------
| subclass | superclass |
===============================================================================================================================================
| <http://dbpedia.org/ontology/FilmFestival> | <http://schema.org/Festival> |
| <http://dbpedia.org/ontology/Embryology> | <http://dbpedia.org/ontology/AnatomicalStructure> |
| <http://dbpedia.org/ontology/Canal> | <http://dbpedia.org/ontology/Stream> |
| <http://dbpedia.org/ontology/Fern> | <http://dbpedia.org/ontology/Plant> |
| <http://dbpedia.org/ontology/Architect> | <http://dbpedia.org/ontology/Person> |
...
| <http://dbpedia.org/ontology/LegalCase> | <http://dbpedia.org/ontology/Case> |
| <http://dbpedia.org/ontology/Lymph> | <http://dbpedia.org/ontology/AnatomicalStructure> |
| <http://dbpedia.org/ontology/City> | <http://dbpedia.org/ontology/Settlement> |
-----------------------------------------------------------------------------------------------------------------------------------------------
Ако искате тези данни като графика, можете да използвате вместо това construct
заявка и ще имате на разположение редица изходни формати:
prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#>
construct where {
?subclass rdfs:subClassOf ?superclass
}
$ sparql --query query.rq --data dbpedia_3.9.owl | head -20
@prefix : <http://dbpedia.org/ontology/> .
@prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#> .
@prefix xsd: <http://www.w3.org/2001/XMLSchema#> .
@prefix owl: <http://www.w3.org/2002/07/owl#> .
@prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> .
:PoloLeague rdfs:subClassOf :SportsLeague .
:RacingDriver rdfs:subClassOf :Athlete .
:ResearchProject rdfs:subClassOf :Project .
# ...
$ sparql -out NT --query query.rq --data dbpedia_3.9.owl | head -20
<http://dbpedia.org/ontology/PoloLeague> <http://www.w3.org/2000/01/rdf-schema#subClassOf> <http://dbpedia.org/ontology/SportsLeague> .
<http://dbpedia.org/ontology/RacingDriver> <http://www.w3.org/2000/01/rdf-schema#subClassOf> <http://dbpedia.org/ontology/Athlete> .
<http://dbpedia.org/ontology/ResearchProject> <http://www.w3.org/2000/01/rdf-schema#subClassOf> <http://dbpedia.org/ontology/Project> .
<http://dbpedia.org/ontology/Song> <http://www.w3.org/2000/01/rdf-schema#subClassOf> <http://dbpedia.org/ontology/MusicalWork> .
<http://dbpedia.org/ontology/NetballPlayer> <http://www.w3.org/2000/01/rdf-schema#subClassOf> <http://dbpedia.org/ontology/Athlete> .
<http://dbpedia.org/ontology/Guitar> <http://www.w3.org/2000/01/rdf-schema#subClassOf> <http://dbpedia.org/ontology/Instrument> .
$ sparql -out RDF/XML --query query.rq --data dbpedia_3.9.owl | head -28
<rdf:RDF
xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns:owl="http://www.w3.org/2002/07/owl#"
xmlns:xsd="http://www.w3.org/2001/XMLSchema#"
xmlns="http://dbpedia.org/ontology/"
xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#">
<rdf:Description rdf:about="http://dbpedia.org/ontology/SpeedwayTeam">
<rdfs:subClassOf>
<rdf:Description rdf:about="http://dbpedia.org/ontology/SportsTeam">
<rdfs:subClassOf>
<rdf:Description rdf:about="http://dbpedia.org/ontology/Organisation">
<rdfs:subClassOf>
<rdf:Description rdf:about="http://dbpedia.org/ontology/Agent">
<rdfs:subClassOf rdf:resource="http://www.w3.org/2002/07/owl#Thing"/>
</rdf:Description>
</rdfs:subClassOf>
</rdf:Description>
</rdfs:subClassOf>
</rdf:Description>
</rdfs:subClassOf>
</rdf:Description>
<rdf:Description rdf:about="http://dbpedia.org/ontology/NoteworthyPartOfBuilding">
<rdfs:subClassOf>
<rdf:Description rdf:about="http://dbpedia.org/ontology/ArchitecturalStructure">
<rdfs:subClassOf>
<rdf:Description rdf:about="http://dbpedia.org/ontology/Place">
<rdfs:subClassOf rdf:resource="http://www.w3.org/2002/07/owl#Thing"/>
</rdf:Description>
<!-- ... -->
person
Joshua Taylor
schedule
19.10.2013
rdfs:subClassOf
отношения между класовете. - person Joshua Taylor   schedule 18.10.2013rdfs:subClass
(и можете да поискате всички неща, които иматrdf:type rdfs:Class
, докато сте там). Можете също така да получите тези резултати програмно чрез модела на Jena и метода listStatements, но SPARQL заявката е може би най-лесният начин. - person Joshua Taylor   schedule 19.10.2013