Нов съм в шифъра. Искам да намеря подобни възли без повтарящи се съвпадения.
Примерни данни
CREATE (r1:Repository {id:"repository1"})
CREATE (r2:Repository {id:"repository2"})
CREATE (r3:Repository {id:"repository3"})
CREATE (a1:Actor {id: "actor1"})
CREATE (a2:Actor {id: "actor2"})
CREATE (a3:Actor {id: "actor3"})
CREATE (o1:Organization {id:"organization1"})
CREATE (o2:Organization {id:"organization2"})
MATCH (a:Repository {id:"repository1"}) MATCH (b:Actor {id: 'actor1'})
CREATE (a)-[:IS_ACTOR]->(b)
MATCH (a:Repository {id:"repository1"}) MATCH (b:Actor {id: 'actor2'})
CREATE (a)-[:IS_ACTOR]->(b)
MATCH (a:Repository {id:"repository1"}) MATCH (b:Actor {id: 'actor3'})
CREATE (a)-[:IS_ACTOR]->(b)
MATCH (a:Repository {id:"repository1"}) MATCH (b:Organization {id:
'organization1'}) CREATE (a)-[:IN_ORGANIZATION]->(b)
MATCH (a:Repository {id:"repository2"}) MATCH (b:Actor {id: 'actor1'})
CREATE (a)-[:IS_ACTOR]->(b)
MATCH (a:Repository {id:"repository2"}) MATCH (b:Actor {id: 'actor2'})
CREATE (a)-[:IS_ACTOR]->(b)
MATCH (a:Repository {id:"repository2"}) MATCH (b:Organization {id:
'organization1'}) CREATE (a)-[:IN_ORGANIZATION]->(b)
MATCH (a:Repository {id:"repository3"}) MATCH (b:Actor {id: 'actor3'})
CREATE (a)-[:IS_ACTOR]->(b)
MATCH (a:Repository {id:"repository3"}) MATCH (b:Organization {id:
'organization2'}) CREATE (a)-[:IN_ORGANIZATION]->(b)
Cypher
MATCH (a)-[r1:IS_ACTOR|IN_ORGANIZATION]->(match)<-
[r2:IS_ACTOR|IN_ORGANIZATION]-(b)
where not a.id = b.id with a,b,count(match) as count, collect (match.id) as
connections, collect (type(r1)) as rel1
return a.id,b.id,count,connections,rel1 order by count desc
Резултат
a.id b.id count connections rel1
repository2 repository1 3 actor1,actor2,organization1 IS_ACTOR, IS_ACTOR,IN_ORGANIZATION
repository1 repository2 3 actor1,actor2,organization1 IS_ACTOR, IS_ACTOR,IN_ORGANIZATION
repository3 repository1 1 actor3 IS_ACTOR
repository1 repository3 1 actor3 IS_ACTOR
Как мога да премахна ред #2 & #4 от резултата?
Въз основа на отговор на подобен въпрос Опитах се да използвам филтър, но получавам синтактична грешка (шифр по-долу)
MATCH (a)-[r1:IS_ACTOR|IN_ORGANIZATION]->(match)<-
[r2:IS_ACTOR|IN_ORGANIZATION]-(b)
with filter(x in connections where x <> b.id)
where not a.id = b.id with a,b,count(match) as count, collect (match.id) as
connections, collect (type(r1)) as rel1
return a.id,b.id,count,connections,rel1 order by count desc